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Q.) If the roots of the equation ( ax^2 + bx + c = 0 ) are of the form ( (k+1)/k ) and (k+2}/k+1), then ( (a + b + c)^2 ) is equal to:
[A]2b^2ac
[B]Σα
[C]b^2 - 4ac
[D]b^2 - 2ac